> True, but most of the other objects near it are also at or near orbital speed,... | Hacker News

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		SideburnsOfDoom on Oct 1, 2015 \| parent \| context \| favorite \| on: The sky's gone dark > True, but most of the other objects near it are also at or near orbital speed, so what's the kinetic energy when compared to an object it would actually be likely to hit? If they're moving in opposite directions, then you just double it.

goodcanadian on Oct 1, 2015 [–]

Actually, I think you quadruple it as kinetic energy goes as v^2.

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