Hacker Newsnew | past | comments | ask | show | jobs | submitlogin

He is wrong in that the sentence of his that I quoted contained two statements: "when the volatility of the underlying security increases, [1] arbitrage pressures push the corresponding binary option to trade closer to 50% and [2] become less variable over the remaining time to expiration." His calculation proves [1], but it's [2] that is the basis of his criticism of Silver. And it's just not true, as can be seen even in a simple random-walk model.


"[2] become less variable over the remaining time to expiration ... And it's just not true, as can be seen even in a simple random-walk model."

Dear @aubreyclayton, I'm genuinely interested in seeing how you arrived at this conclusion. Would you kindly share the proof, or at least explain the logic behind it. Thank you.


Sure. If you've studied stochastic processes like Brownian motion, check out the derivation starting with the last paragraph on p.4 of this note: https://drive.google.com/file/d/1tQj4ZGja6jKADJGiFj-dcQAirWo...

If that's foreign to you, you might be interested in this write-up I did about election-forecasting in which I considered the same example, just in discrete time rather than continuous time: http://nautil.us/issue/70/variables/how-to-improve-political...

The basic idea is that if you increase the volatility of a random-walk process, say by making the step-sizes larger, that won't actually make the probability of finishing above where you started any less (or more) volatile. The higher volatility means that from any given starting point your final resting place is more dispersed, but you're also more likely to range farther from home as you go. The two effects exactly cancel. Taleb's critique misses the second part of that.


Thank you.


Prove it.




Consider applying for YC's Fall 2025 batch! Applications are open till Aug 4

Guidelines | FAQ | Lists | API | Security | Legal | Apply to YC | Contact

Search: