Then you'll have a capacitor with a larger plate separation. Play with the equations!

http://hyperphysics.phy-astr.gsu.edu/hbase/electric/pplate.h...

Ok now we’re getting somewhere.

So the equation shows that as d goes up, C goes down.

But as d goes up the breakdown voltage also increases so my question is why can’t we force more voltage on there.

You can but eventually the voltage gets so high that the resistance of the air isn't enough to prevent a short via a discharge. And in a vacuum, the resistance is even less. One would have to keep the capacitor in a super resistant gas or fluid to prevent a short.

Yeah that’s what I’m trying to figure out. Maybe energy storage wise it’s worth encasing it in a large amount of high insulator.

I’m curious to run those numbers but I’m not quite sure how to approach it.

That's basically increasing the breakdown voltage, no? Even if the "gap" between plates is 4 meters of insulation.