If you look at the linked issue, you will see that it is a type intersection iss...

anonymoushn · on June 26, 2022

As an end user it may be hard for me to accept that there are no control-flow bugs involved when this code

    println(flag)
    if flag
        println("flow for true.")
    else
        println("flow for false.")
    end

prints

  false
  flow for true.

oivey · on June 26, 2022

I pasted that code into a REPL (including setting flag=false, which seems to be implied) and got:

  false
  flow for false.

How did you get your output? Your post implies that if statements are broken in Julia. Untrue.

jakobnissen · on June 26, 2022