this doesn't look like log to me. i think the function you want is e'th root. | Hacker News

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benmmurphy on Aug 10, 2013 | parent | context | favorite | on: Math Advances Suggest RSA Encryption Could Fall Wi...

this doesn't look like log to me. i think the function you want is e'th root.

barrkel on Aug 10, 2013 [–]

n'th root of x = exp(log(x) / n)

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