then you'd get \n \n fizz\n \n buzz\n rather than fizz\n buzz\n | Hacker News

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		zem on Dec 11, 2014 \| parent \| context \| favorite \| on: Streem – a new programming language from Matz then you'd get \n \n fizz\n \n buzz\n rather than fizz\n buzz\n

dllthomas on Dec 11, 2014 [–]

The canonical FizzBuzz wants

1\n2\nFizz\n4\nBuzz\n...\nFizzBuzz\n

If you did not print anything for some cases, you're right that it could not be unconditional (though it could still be done at the end with a flag).

zem on Dec 11, 2014 | [–]

oops, yes, my mistake.

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