char theLetterC = 2["ABC"]; Wait, what? And I thought I was good with pointers..... | Hacker News

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		danlugo92 on Dec 3, 2018 \| parent \| context \| favorite \| on: Pointers in C (2010) `char theLetterC = 2["ABC"];` Wait, what? And I thought I was good with pointers... Edit: I think I got it, is it this?: "ABC" + 2 == 2["ABC"] == *(2 + "ABC") Right?

aasasd on Dec 3, 2018 [–]

I'm not a C man, but afaiu, "ABC" is syntactic sugar for a char pointer to that string. So it works like any pointer with regard to index access.

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